alleryStart learning →A rope on pegs X, Y is pulled tight at its midpoint A. Why is A on the perpendicular bisector?
AThe rope is long
BA is as far from X as Y
CA is on a circle at X
DThe pegs are upright
Answer & Solution
Correct answer: B. A is as far from X as Y
The two halves of the rope are equal, so AX = AY, and such a point lies on the perpendicular bisector.
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