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In 53*0 a digit * is missing. Which value makes the number a multiple of 6?

A2
B3
C5
D7
Answer & Solution
Correct answer: D. 7
The number ends in 0 so it is even, and 5 + 3 + * must be a multiple of 3. Only 7 gives 15; 2, 3 and 5 give 10, 11 and 13.
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