alleryStart learning →Multiplying x=5 by zero gives 0=0. How does this change the solution set over the reals?
AIt removes every solution
BIt leaves only x=0
CIt admits every real x
DIt leaves only x=5
Answer & Solution
Correct answer: C. It admits every real x
The original equation permits only 5. The equation 0=0 holds for every real x, so multiplication by zero loses the original restriction.
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