Per NCERT, for n = 3 the TOTAL number of orbitals is which value?
A6
B18
C3
D9 (one 3s + three 3p + five 3d, also from n² = 3² = 9)
Answer & Solution
Correct answer: D. 9 (one 3s + three 3p + five 3d, also from n² = 3² = 9)
Per NCERT Problem 2.17, n = 3 ⇒ 3s (1) + 3p (3) + 3d (5) = 9. Also n² rule: 3² = 9.
Related questions
Per NCERT §2.6.6, the actual ground-state valence configurations of CHROMIUM (Z = 24) and Per NCERT (Pauli, 1926), which statement most precisely captures the EXCLUSION PRINCIPLE?Per NCERT §2.6.4 (Aufbau), what is the standard filling order of orbitals in the ground stPer NCERT §2.6.3, in a MULTI-electron atom the energy of an orbital depends on which quantPer NCERT §2.6.2 (last paragraph), the TOTAL number of nodes in an orbital (radial + angulPer NCERT §2.6.2 + Fig. 2.14, how many p-orbitals exist in a given p-subshell, and what shPer NCERT §2.6.2, what is the shape of an s-orbital, and how many radial NODES does an ns Per NCERT, the electron-spin quantum number m_s — introduced by Uhlenbeck and Goudsmit (19