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As per your syllabus, for n = 3 the TOTAL number of orbitals is which value?
A6
B18
C3
D9 (one 3s + three 3p + five 3d, also from n² = 3² = 9)
Answer & Solution
Correct answer: D. 9 (one 3s + three 3p + five 3d, also from n² = 3² = 9)
As per your syllabus, n = 3 ⇒ 3s (1) + 3p (3) + 3d (5) = 9. Also n² rule: 3² = 9.
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