Per NCERT eqn 2.17, the energy gap ΔE between two stationary states n_i and n_f in hydrogen is which expression?
AΔE = R_H × n_i × n_f
BΔE = R_H / (n_i² + n_f²)
CΔE = R_H (1/n_i² − 1/n_f²) = 2.18 × 10⁻¹⁸ J × (1/n_i² − 1/n_f²)
DΔE = R_H (n_i + n_f)
Answer & Solution
Correct answer: C. ΔE = R_H (1/n_i² − 1/n_f²) = 2.18 × 10⁻¹⁸ J × (1/n_i² − 1/n_f²)
Per NCERT eqn 2.17, ΔE = R_H (1/n_i² − 1/n_f²). For emission n_i > n_f → ΔE < 0 (released).
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