Per NCERT eqn 2.22, the de Broglie wavelength λ of a particle of momentum p (or mass m, velocity v) is which expression?
Aλ = m v / h
Bλ = h / (m v) = h / p
Cλ = h × m × v
Dλ = h × p
Answer & Solution
Correct answer: B. λ = h / (m v) = h / p
Per NCERT eqn 2.22, λ = h/p (de Broglie 1924). Confirmed experimentally by electron diffraction.
Related questions
Per NCERT Problem 2.16 (golf ball, mass 40 g, 2% speed uncertainty), why does the uncertaiPer NCERT eqn 2.17, the energy gap ΔE between two stationary states n_i and n_f in hydrogePer NCERT §2.5.2 (significance), what is the key consequence of the uncertainty principle Per NCERT eqn 2.23, Heisenberg's uncertainty principle (1927) states which inequality betwPer NCERT Table 2.3, the LYMAN series (n₁ = 1) of hydrogen lines lies in which spectral rePer NCERT Problem 2.6, what is the energy of one mole of photons of radiation of frequencyPer NCERT eqn 2.7, Einstein's photoelectric equation gives the kinetic energy of an ejectePer NCERT §photoelectric effect, which of the following classical predictions does the pho