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Find the odd pair out, where the second number is 3 times the first: (3, 9), (4, 12), (5, 15), (6, 20).

A(5, 15)
B(6, 20)
C(4, 12)
D(3, 9)
Answer & Solution
Correct answer: B. (6, 20)
3x3=9, 4x3=12 and 5x3=15, but 6x3=18, not 20, so (6, 20) breaks the rule.
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