Home › CLAT (NLU Prep) › quantitativeaptitude › quantitative_techniques › A train 200 m long crosses a stationary pole in …
A train 200 m long crosses a stationary pole in 10 seconds. Its speed in km/h is
A75
B80
C60
D72
Answer & Solution
Correct answer: D. 72
Speed = distance/time = 200/10 = 20 m/s. Convert: 20 × 18/5 = 72 km/h.
Related questions
Read the following data and answer the questions that follow.
A law firm has 200 employeeRead the following data and answer the questions that follow.
A law firm has 200 employeeRead the following data and answer the questions that follow.
A law firm has 200 employeeThe sum of the first 20 natural numbers (1 + 2 + … + 20) equalsIn an arithmetic progression with first term 3 and common difference 4, the 10th term isIf the principal doubles in 8 years at simple interest, the annual rate isFind the compound interest on Rs 10,000 at 10% per annum compounded annually for 2 years.The simple interest on Rs 5,000 at 10% per annum for 2 years is