For arbitrary sets A and B, simplify A ∪ (A ∩ B) and A ∩ (A ∪ B), in that order.
AA and A
BB and A
CA and B
DB and B
Answer & Solution
Correct answer: A. A and A
A intersection B adds no element outside A; every element of A is already in A union B, so both expressions equal A.
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