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The 20th term of the sequence aₙ = (n − 1)(2 − n)(3 + n) is
A0
B−7866
C+7866
D−6534
Answer & Solution
Correct answer: B. −7866
a₂₀ = (19)(2 − 20)(3 + 20) = 19 × (−18) × 23 = −7866.
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