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Energy stored in an inductor carrying current I is
AU = L / (2 I²)
BU = LI
CU = (1/2) L I²
DU = L² I
Answer & Solution
Correct answer: C. U = (1/2) L I²
U = ½ L I². Analogous to ½ C V² for a capacitor and ½ m v² for a moving mass — quadratic in the conserved quantity.
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