alleryThe equatorial field of a short bar magnet of moment m at large distance r is
A(μ₀/4π) · (m / r²)
BZero
C(μ₀/4π) · (2m / r³)
D(μ₀/4π) · (m / r³), directed opposite to m
Answer & Solution
Correct answer: D. (μ₀/4π) · (m / r³), directed opposite to m
Equatorial field magnitude is half the axial field at the same distance, directed opposite to m: B_eq = −(μ₀/4π)(m/r³).
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