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For integer n, factor 2^n + 2^(n+1).

A3 × 2^(n+1)
B2^(2n+1)
C2^(n+2)
D3 × 2^n
Answer & Solution
Correct answer: D. 3 × 2^n
The second term is twice the first, so their sum is three times 2 to the power n.
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