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Per NCERT Problem 1.2, what is the MOLECULAR formula of the compound (empirical CH₂Cl, molar mass 98.96 g)?
ACH₂Cl
BC₂H₄Cl₂ (since 98.96 / 49.48 = 2; multiply empirical by 2)
CCHCl
DC₃H₆Cl₃
Answer & Solution
Correct answer: B. C₂H₄Cl₂ (since 98.96 / 49.48 = 2; multiply empirical by 2)
Per NCERT Problem 1.2 Step 5, empirical CH₂Cl mass = 49.48; n = 98.96/49.48 = 2 → molecular = C₂H₄Cl₂ (1,2-dichloroethane).
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