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Per NCERT Problem 1.2, a compound has 4.07% H, 24.27% C, 71.65% Cl, with molar mass 98.96 g. What is its EMPIRICAL formula?
ACH₂Cl (after dividing moles by smallest, ratio H:C:Cl = 2:1:1)
BCH₂Cl₂
CCHCl₂
DC₂H₄Cl₂ (this is the molecular formula)
Answer & Solution
Correct answer: A. CH₂Cl (after dividing moles by smallest, ratio H:C:Cl = 2:1:1)
Per NCERT Problem 1.2 Step 3+4, moles H/C/Cl = 4.04/2.021/2.021 = 2/1/1. Empirical = CH₂Cl.
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