Per NCERT Problem 1.2, a compound has 4.07% H, 24.27% C, 71.65% Cl, with molar mass 98.96 g. What is its EMPIRICAL formula?
ACH₂Cl (after dividing moles by smallest, ratio H:C:Cl = 2:1:1)
BCH₂Cl₂
CCHCl₂
DC₂H₄Cl₂ (this is the molecular formula)
Answer & Solution
Correct answer: A. CH₂Cl (after dividing moles by smallest, ratio H:C:Cl = 2:1:1)
Per NCERT Problem 1.2 Step 3+4, moles H/C/Cl = 4.04/2.021/2.021 = 2/1/1. Empirical = CH₂Cl.
Related questions
Per NCERT, the MASS PER CENT of an element in a compound is calculated using which formulaPer NCERT Problem 1.2, what is the MOLECULAR formula of the compound (empirical CH₂Cl, molPer NCERT, the empirical formula of glucose is CH₂O. Given molar mass = 180 g/mol, what isPer NCERT, what is the MOLECULAR formula of a compound?Per NCERT, what is the EMPIRICAL formula of a compound?Per NCERT, what is the MASS PERCENTAGE of oxygen in WATER (H₂O)?Per NCERT, what is the MASS PERCENTAGE of hydrogen in WATER (H₂O) — given molar masses C=1Per NCERT, 1 mole of WATER MOLECULES contains how many water molecules?