Per NCERT, a ball thrown vertically upward with initial velocity v₀ reaches maximum height h. What is h in terms of v₀ and g?
Ah = 2v₀/g
Bh = v₀/g
Ch = v₀² × g
Dh = v₀² / (2g) (using v² = v₀² − 2gh with v = 0 at the top)
Answer & Solution
Correct answer: D. h = v₀² / (2g) (using v² = v₀² − 2gh with v = 0 at the top)
Per NCERT, at top v = 0; using v² = v₀² − 2gh → h = v₀²/(2g).
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