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As per your syllabus, how long does the same car (initial 35 m/s, retardation 3.06 m/s²) take to stop?
AAbout 5 s
BAbout 200 s
CAbout 35 s
DAbout 11.4 s (using v = v₀ + at with v = 0)
Answer & Solution
Correct answer: D. About 11.4 s (using v = v₀ + at with v = 0)
As per your syllabus, 0 = 35 + (−3.06)t → t ≈ 11.4 s.
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