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As per your syllabus, a car at 126 km/h (= 35 m/s) brakes to stop in 200 m. What is its retardation (assumed uniform)?
A0.5 m/s²
B3.06 m/s² (using v² = v₀² + 2ax with v=0)
C6.25 m/s²
D35 m/s²
Answer & Solution
Correct answer: B. 3.06 m/s² (using v² = v₀² + 2ax with v=0)
As per your syllabus, 0 = 35² + 2(−a)(200)
→ 2a × 200 = 1225 → a ≈ 3.06 m/s² retardation.
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