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A closed loop contains a source of $24\,\text{V}$ and two known voltage drops of $9\,\text{V}$ and $6\,\text{V}$. What is the remaining voltage drop?
A$7\,\text{V}$
B$9\,\text{V}$
C$15\,\text{V}$
D$39\,\text{V}$
Answer & Solution
Correct answer: B. $9\,\text{V}$
By KVL, the source voltage equals the sum of the drops in the loop. So the unknown drop is $24-9-6=9\,\text{V}$. This follows from balancing one voltage rise against the total voltage drops.