For a GP with first a, ratio r≠1 and positive integer n, Sₙ equals
Aa(1−r)/(1−rⁿ)
Ba(1−rⁿ⁻¹)/(1−r)
Ca(1−rⁿ)/(1−r)
Dar(1−rⁿ)/(1−r)
Answer & Solution
Correct answer: C. a(1−rⁿ)/(1−r)
The first n powers from r⁰ to rⁿ⁻¹ sum to (1−rⁿ)/(1−r), multiplied by a.
Keep practising Arithmetic & Geometric Progressions
Browse all Arithmetic & Geometric Progressions questions for ICSE Class 10, or explore more Mathematics topics.
Related questions
Match each Arithmetic Progression (AP) formula with its quantity:Match each AP selection strategy with the chosen symmetric variables:Match each sequence computation with its evaluated answer:Match each AP sequence with its common difference d:Insert two positive geometric means between 2 and 54. What is the first inserted?A GP starts a,ar,ar² with a,r>0. If a+ar=6 and ar+ar²=18, r equalsThree positive numbers are consecutive terms of both an AP and a GP. They must beAn asset keeps 80% of its value each year. Initially ₹500, its value after 3 years?