An AP has 2n terms, first a and last l, n a positive integer. Its mean is
A(a+l)/(2n)
B2(a+l)
C(a+l)/2
Dn(a+l)
Answer & Solution
Correct answer: C. (a+l)/2
Dividing the sum n(a+l) by the term count 2n gives the average (a+l)/2.
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