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An AP has a>0,d>0 and a₃:a₇=2:5. Find a:d.

A3:2
B2:3
C5:2
D2:5
Answer & Solution
Correct answer: B. 2:3
The equation 5(a+2d)=2(a+6d) gives 3a=2d, hence a:d=2:3.
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