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Factor tan²A−sin²A completely for 0°<A<90°.

Acot²A cos²A
Bsin²A cos²A
Ctan²A sin²A
Dtan²A cos²A
Answer & Solution
Correct answer: C. tan²A sin²A
Factoring sin²A(1/cos²A − 1) gives tan²A sin²A.
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