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As per your syllabus, for the same convex lens problem (f=+10, u=−15), what is the MAGNIFICATION?

A+2
B+1/2
C−2 (image is twice as tall and INVERTED — real)
D−1/2
Answer & Solution
Correct answer: C. −2 (image is twice as tall and INVERTED — real)
As per your syllabus, m = v/u = 30/(−15) = −2. Negative sign indicates inverted real image magnitude 2 indicates twice enlarged.
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