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Per NCERT Example 9.1, for the same problem (convex mirror, bus at 5 m), what is the MAGNIFICATION of the image?
A+5.00
B+0.23 (virtual erect diminished image)
C−0.23
D−5.00
Answer & Solution
Correct answer: B. +0.23 (virtual erect diminished image)
Per NCERT Example 9.1, m = −v/u = −1.15/(−5) = +0.23. Positive → virtual + erect. Small magnitude → diminished.
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