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In convex trapezium ABCD, AB∥CD. Diagonals meet at O; AB:CD=2:3. AO:OC?

A1:3
B3:2
C2:3
D4:9
Answer & Solution
Correct answer: C. 2:3
AA similarity of triangles AOB and COD gives AO/OC=AB/CD=2/3.
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