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Which identity proves x+1 is a factor of x³+1?

Ax³+1=(x+1)(x²−x−1)
Bx³+1=(x+1)(x²−x+1)
Cx³+1=(x−1)(x²+x+1)
Dx³+1=(x+1)(x²+x+1)
Answer & Solution
Correct answer: B. x³+1=(x+1)(x²−x+1)
Expanding (x+1)(x²−x+1) gives x³+1 because the middle terms cancel.
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