The complete factorisation of x³−4x²+5x−2 is
A(x−1)²(x+2)
B(x+1)²(x−2)
C(x−1)(x−2)²
D(x−1)²(x−2)
Answer & Solution
Correct answer: D. (x−1)²(x−2)
Removing x−1 leaves x²−3x+2=(x−1)(x−2), giving the repeated factor x−1.
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