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Normal entry: 30° prism in air, n=1.5. Given sin^-1(0.75)=48.6°. Deviation?

A78.6°
B48.6°
C30°
D18.6°
Answer & Solution
Correct answer: D. 18.6°
Normal entry gives r2=30° and exit angle 48.6°, making deviation 0°+48.6°-30°=18.6°.
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