A binary solution of two volatile liquids A (P°₁ = 450 mm Hg) and B (P°₂ = 700 mm Hg) at 350 K has a total vapour pressure of 600 mm Hg. The mole fraction of B in the liquid phase is:
A0.7
B0.4
C0.6
D0.3
Answer & Solution
Correct answer: C. 0.6
$P = (P_2^0 - P_1^0)x_2 + P_1^0 = 250 x_2 + 450 = 600$ ⇒ $x_2 = 150/250 = 0.6$. (Hence $x_1 = 0.4$.)
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