Multiply [[1, −2], [3, 0]] by 2.
A[[2, −4], [6, 0]]
B[[2, −2], [3, 0]]
C[[1, −4], [6, 0]]
D[[2, 4], [6, 0]]
Answer & Solution
Correct answer: A. [[2, −4], [6, 0]]
Multiplying each entry by 2 gives [[2, −4], [6, 0]].
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