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Select the reduction equation for Pb2+ in molten lead bromide.

A2Br− → Br2 + 2e−
BPb → Pb2+ + 2e−
CPb2+ + 2e− → Pb
DBr2 + 2e− → 2Br−
Answer & Solution
Correct answer: C. Pb2+ + 2e− → Pb
Lead ions gain two electrons to form lead at the cathode.
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