Work done in moving a 6 C charge between two points raises the system's potential energy by 120 J. If the starting potential is 10 V, the final potential is:
A20 V
B30 V
C130 V
D120 V
Answer & Solution
Correct answer: B. 30 V
$V_B - V_A = W_{AB}/q = 120/6 = 20$ V, so $V_B = 10 + 20 = 30$ V.
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