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Per NCERT, an object falling FREELY from height h (released from rest) — what is the velocity v at the bottom (just before hitting ground), using conservation of mechanical energy?
Av = ½ g h
Bv = gh
Cv = 2 g h
Dv = √(2gh)
Answer & Solution
Correct answer: D. v = √(2gh)
Per NCERT Example 7.8 (the slide example), conservation gives ½mv² = mgh, so v = √(2gh). The other formulas misstate.
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