allerysec²θ ରୁ tan²θ ବିୟୋଗ କଲେ ସର୍ବଦା କେଉଁ ଧ୍ରୁବକ ବଳକା ରହେ?
A2
B0
C1
D−1
Answer & Solution
Correct answer: C. 1
(sin²θ + cos²θ = 1) କୁ cos²θ ଦ୍ୱାରା ଭାଗ କଲେ tan²θ + 1 = sec²θ ମିଳିଥାଏ, ତେଣୁ sec²θ - tan²θ = 1।
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