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12 सेंमी.च्या बाजूच्या समबाहु त्रिकोणाची उंचाय कितली आसता?

A9 cm
B6√2 cm
C6 cm
D6√3 cm
Answer & Solution
Correct answer: D. 6√3 cm
उंचायेचेर आदाराचे 6 आनी 6 अशे विभाग जातात, देखून तो 144 - 36 = 108 चें वर्गमूळ आसून तें 6√3 सेंमी.
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