एका समभुज चौकोनाची बाजू 10 cm आणि एक कर्ण 12 cm आहे. त्याचे क्षेत्रफळ किती?
A96 cm²
B60 cm²
C120 cm²
D192 cm²
Answer & Solution
Correct answer: A. 96 cm²
एका कर्णाचा निम्मा भाग 6 cm आणि बाजू 10 cm वरून दुसऱ्या कर्णाचा निम्मा भाग 8 cm मिळतो; त्यामुळे 12 cm आणि 16 cm कर्ण असल्यास क्षेत्रफळ = (1/2) × 12 × 16 = 96 cm² मिळते.
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