allery7 ಸೆಂ.ಮೀ ತ್ರಿಜ್ಯ ಹೊಂದಿರುವ ಒಂದು ಶಂಕುವಿನ ಗಾತ್ರ 154 ಸೆಂ.ಮೀ³ (ಪೈ = 22/7) ಹೊಂದಿದೆ. ಅದರ ಎತ್ತರ ಎಷ್ಟು?
A6 cm
B1 cm
C9 cm
D3 cm
Answer & Solution
Correct answer: D. 3 cm
(1/3)(22/7)(49)h = 154 ನಿಂದ ನಾವು (154/3)h = 154 ಅನ್ನು ಪಡೆಯುತ್ತೇವೆ, ಆದ್ದರಿಂದ h = 3 ಸೆಂ.ಮೀ.
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