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ଗୋଟିଏ ସମକୋଣୀ ତ୍ରିଭୁଜର ସମକୋଣ ସଂଲଗ୍ନ ବାହୁଦ୍ୱୟ 9 cm ଏବଂ 12 cm ଅଟେ। ଏହାର ପରିସୀମା କେତେ?

A36 cm
B21 cm
C30 cm
D54 cm
Answer & Solution
Correct answer: A. 36 cm
କର୍ଣ୍ଣ ହେଉଛି 81 + 144 ର ବର୍ଗମୂଳ, ଯାହା 15 ଅଟେ, ତେଣୁ ପରିସୀମା ହେଉଛି 9 + 12 + 15 = 36 cm।
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