ଗୋଟିଏ ଟ୍ରାପିଜିୟମର ସମାନ୍ତରାଳ ବାହୁଦ୍ୱୟ 10 cm ଏବଂ 16 cm, ଏବଂ ସେମାନଙ୍କ ମଧ୍ୟବର୍ତ୍ତୀ ଦୂରତା 8 cm ଅଟେ। ଏହାର କ୍ଷେତ୍ରଫଳ ନିର୍ଣ୍ଣୟ କରନ୍ତୁ।
A104 cm²
B208 cm²
C128 cm²
D80 cm²
Answer & Solution
Correct answer: A. 104 cm²
କ୍ଷେତ୍ରଫଳ ହେଉଛି ସମାନ୍ତରାଳ ବାହୁଦ୍ୱୟର ସମଷ୍ଟିର ଅର୍ଦ୍ଧେକ ଗୁଣନ ସେମାନଙ୍କ ମଧ୍ୟବର୍ତ୍ତୀ ଦୂରତା: 0.5 x 26 x 8 = 104 square centimetres।
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