एका समलंब चौकोनाच्या समांतर बाजू 10 cm आणि 16 cm असून, त्या एकमेकांपासून 8 cm अंतरावर आहेत. त्याचे क्षेत्रफळ काढा.
A104 cm²
B208 cm²
C128 cm²
D80 cm²
Answer & Solution
Correct answer: A. 104 cm²
क्षेत्रफळ हे समांतर बाजूंच्या बेरजेच्या निम्मे गुणिले त्यांच्यातील अंतर असते: 0.5 x 26 x 8 = 104 चौरस सेंटीमीटर.
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