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Three resistors of 3 Ω, 4 Ω and 5 Ω are in series. Find total resistance.

A60 Ω
B8 Ω
C12 Ω
D7 Ω
Answer & Solution
Correct answer: C. 12 Ω
Series resistance is 3+4+5 = 12 Ω.
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