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ꯖꯤ.ꯁꯤ.ꯗꯤ.ꯅꯥ ꯑꯦꯁꯣꯁꯤꯑꯦꯇꯤꯕ ꯑꯣꯏ꯫ ꯀꯔꯝꯕꯥ ꯑꯦꯛꯁꯞꯔꯦꯁꯟꯅꯥ gcd(a, gcd(b, c))ꯒꯥ ꯃꯥꯟꯅꯕꯒꯦ?

Agcd(a x b, c)
Bꯑꯦꯜ.ꯁꯤ.ꯑꯦꯝ.(ꯀ, ꯕꯤ, ꯁꯤ)
Cgcd(gcd(a, b), c)
Dgcd(a, b) + c
Answer & Solution
Correct answer: C. gcd(gcd(a, b), c)
ꯑꯦꯁꯣꯁꯤꯑꯦꯇꯤꯕꯤꯇꯤꯅꯥ ꯖꯤ.ꯁꯤ.ꯗꯤ.ꯒꯤ ꯂꯧꯕꯥ ꯃꯇꯃꯗꯥ ꯅꯝꯕꯔ ꯑꯍꯨꯝ ꯑꯁꯤ ꯑꯣꯔꯗꯔ ꯑꯃꯍꯦꯛꯇꯗꯥ ꯒ꯭ꯔꯨꯞ ꯇꯧꯕꯥ ꯌꯥꯍꯜꯂꯤ꯫
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