alleryयूक्लिड की विभाजन विधि का उपयोग करके, 252 और 105 का HCF क्या है?
A14
B7
C42
D21
Answer & Solution
Correct answer: D. 21
252 = 2 x 105 + 42, 105 = 2 x 42 + 21, 42 = 2 x 21 + 0। अंतिम अशून्य शेषफल 21 है, अतः HCF = 21।
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