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As per your syllabus, a CYCLIC quadrilateral has sides 3, 4, 5, 6. What is its area (using Brahmagupta's formula)?

A30 square units
B18 square units
C√[3 × 4 × 5 × 6] = √360 square units
D6√10 square units
Answer & Solution
Correct answer: D. 6√10 square units
s = (3+4+5+6)/2 = 9; area = √[(9−3)(9−4)(9−5)(9−6)] = √(6×5×4×3) = √360 = 6√10 sq units. The other options misapply.
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