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Per NCERT, what is BRAHMAGUPTA's FORMULA for the area of a CYCLIC quadrilateral with sides a, b, c, d and semi-perimeter s?
A(s−a)(s−b)(s−c)(s−d)
Bs² − (a + b + c + d)²
C√[(s−a)(s−b)(s−c)(s−d)]
D√[s(s−a)(s−b)(s−c)(s−d)]
Answer & Solution
Correct answer: C. √[(s−a)(s−b)(s−c)(s−d)]
Brahmagupta's formula: area of a cyclic 4-gon = √[(s−a)(s−b)(s−c)(s−d)]. The other options misstate.
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