Per NCERT, what is the perimeter of a shape obtained by joining a SEMICIRCLE (diameter d) along the top of a square (side d) — measured as the total length around the new compound shape (excluding the diameter that's no longer a boundary)?
A3d + πd/2 (three sides of the square + the semicircular arc)
Bd + πd/2
C4d + πd
D3d + πd
Answer & Solution
Correct answer: A. 3d + πd/2 (three sides of the square + the semicircular arc)
Three open sides of the square (3d) + the semicircular arc (πd/2). The other options either over-count or under-count.
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