Solve -3x + 5 > 2 over real numbers.
Ax > 1
Bx < -1
Cx > -1
Dx < 1 (subtract 5: -3x > -3; divide by -3 with sign flip: x < 1)
Answer & Solution
Correct answer: D. x < 1 (subtract 5: -3x > -3; divide by -3 with sign flip: x < 1)
-3x + 5 > 2 → -3x > -3 → divide by -3, FLIP sign → x < 1. Solution: {x ∈ ℝ : x < 1}, i.e. (-∞, 1).
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