A wave is described by $y=A\sin(\omega t-kx)$. This wave propagates in which direction?
AAlong the $+x$ direction
BAlong the $-x$ direction
CIt does not propagate; it is a standing wave
DIts direction cannot be determined from the equation
Answer & Solution
Correct answer: A. Along the $+x$ direction
For a travelling wave, the form $y=A\sin(\omega t-kx)$ or equivalently $A\sin(kx-\omega t)$ represents motion in the $+x$ direction. The form with $\omega t+kx$ corresponds to propagation in the $-x$ direction.
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